3(x-2)-[2(3x-1)-3] =
=3x - 6 -[6x - 2 - 3]=
=3x - 6 -[6x-5]=
=3x - 6 - 6x+5 =
=-3x-1
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3(x-2)-[2(3x-1)-3] =
=3x - 6 -[6x - 2 - 3]=
=3x - 6 -[6x-5]=
=3x - 6 - 6x+5 =
=-3x-1