Prosze o pomoc w obliczeniach PRZYKŁAD. : Fe2O3 2mFe/3mo = 2*56u/3*16u =7/3
Tym razem trzeba obliczyć :
-Cl2O5
- SO2
CL2O5=2*35u+5*16u=70u+80u=150u
SO2=32u+2*16=32u+32u=64u
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CL2O5=2*35u+5*16u=70u+80u=150u
SO2=32u+2*16=32u+32u=64u