oblicz:
2) (4i7/9 +5i1/4) - [(1i7/12 + 3i1/2) - 2i5/6]=
3) 5i5/12 - [(4i2/3 -3i9/10)+2i1/6] - 1i1/2=
4)[1i7/10 + 2i5/8 +(5i1/2 -4i3/5)] + 3i1/4=
5) 1i7/12 +[2i1/2 +4i3/4 -(51/6 -3i2/3)]=
Prosze kto 1 rozwiąze i dobrze dostanie naj:)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2) (4i7/9 +5i1/4) - [(1i7/12 + 3i1/2) - 2i5/6]=
(43/9 + 21/4) - [(19/12 + 7/2) - 17/6] = (43/9 + 21/4) - [(19/12 + 42/12) - 17/6] = (43/9 + 21/4) - [61/12 - 17/6] = (43/9 + 21/4) - [61/12 - 34/12] = (43/9 + 21/4) - 27/12 = (172/36 + 189/36) - 27/12 = 361/36 - 27/12 = 361/36 - 81/36 = 280/36
3) 5i5/12 - [(4i2/3 -3i9/10)+2i1/6] - 1i1/2=
65/12 - [(14/3 - 39/10)+13/6] - 3/2 =
65/12 - [ (140/30 - 117/30) + 13/6] - 3/2=
65/12 - [ 23/30 + 13/6 ] - 3/2 =
65/12 - [ 23/30 + 65/30 ] - 3/2 =
65/12 - 88/30 - 3/2 = 325/60 - 176/60 - 3/2 = 149/60 - 3/2 = 149/60 - 90/60 = 59/60
4) [1i7/10 + 2i5/8 +(5i1/2 -4i3/5)] + 3i1/4=
[17/10+21/8 + (11/2 - 23/5) ] + 13/4 = [17/10+21/8 + (55/10 - 46/10) ] + 13/4
= [17/10+21/8 + 9/10 ] + 13/4 = [136/80+210/80 + 9/10 ] + 13/4 = [346/80 + 9/10 ] + 13/4
= [346/80 + 72/80 ] + 13/4 = 418/80 + 13/4 = 418/80 + 260/80 = 678/80 = 8,475
5) 1i7/12 +[2i1/2 +4i3/4 -(51/6 -3i2/3)]=
19/12 + [ 5/2 + 19/4 - (51/6 - 11/3 ) ] = 19/12 + [ 5/2 + 19/4 - (51/6 - 22/6 ) ] =
19/12 + [ 5/2 + 19/4 - 29/6 ] = 19/12 + [ 10/4+ 19/4 - 29/6 ] = 19/12 + [ 29/4 - 29/6 ]
= 19/12 + [ 87/12 - 58/12 ] = 19/12 + 29/12 = 48/12 = 4
Chyba nic nie przeoczyłem.. Dużo tego :). Mam nadzieję, że pomogłem.