Question

2x(0,3) Do potęgi -1 + 4x8 do potęgi 2/3 - 12x27 do potęgi -1/3

Answer 1

2x(0,3)^(-1) + 4x8^(2/3) - 12x27^(-1/3) =

 

2 x (3/10)^(-1) + 4 x( 8^2)^(1/3) - 12 x (1/27)^(1/3) =

 

2 x 10/3 + 4 x 64^(1/3) - 12 x ∛(1/27) =

 

20/3 + 4 x ∛64 - 12 x 1/3 = 20/3 + 4 x 4 - 4 = 6 i 2/3 + 16 - 4 = 18 i 2/3