Bardzo proszę rozwiązać mi te równania
2+3/x+3=2x-1/x-3, 1/x-1=3/2x-1 oraz 6/x=2/3
Daje naj
2+3\x+3=2x-1\x-3
2x+3+3x=2x²-1-3x
-2x²+8x+4 \(-2)
x²-4x-2 Δ=b²-4ac=(-4)²-4*1*(-2)=√20=2√5
x1=-b\√Δ \ 2a=4-2√5\2*1=4-2√5\2=2-2√5 x2=2+2√5
1\x-1=3\2x-1
1-1x=3-2x
x=2
6\x=2\3
2x=18\2
x=9
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2+3\x+3=2x-1\x-3
2x+3+3x=2x²-1-3x
-2x²+8x+4 \(-2)
x²-4x-2 Δ=b²-4ac=(-4)²-4*1*(-2)=√20=2√5
x1=-b\√Δ \ 2a=4-2√5\2*1=4-2√5\2=2-2√5 x2=2+2√5
1\x-1=3\2x-1
1-1x=3-2x
x=2
6\x=2\3
2x=18\2
x=9