Question

a)Dla x = 3 1/3
x- {x-[x-(x+1)-(x-1)-x]+(1-x)}

b) dla a= -1/3 b= 4,5 c= -1 x=3 1/3 y= 0,7 z=5
abc-(abc-(-xyz-(xyz-abc)))

c) dla s=0,2 t= -5
s2t-(st2- (s2t - (st2- s2t)))

d) dla x=3 1/3 y= 0,7 z=5
x2yz-(xy2z-(xyz2-(x2yz-xy2z)))


Oppowiedzi powinne wyjśc wam takie
a) -4 1/3
b)21 5/6
c) -10,6
d) 58 1/3

Answer 1

a)Dla x = 3 1/3
x- {x-[x-(x+1)-(x-1)-x]+(1-x)}  wystarczy opuszczać nawiasy i upraszczać

x- x +[x-(x+1)-(x-1)-x] - (1-x) =

x - (x+1)- (x-1) - x  - (1-x) =

- (x+1)- (x-1) - (1-x) =

- x - 1 - x + 1 - 1 + x =

- x - 1 = - (3 i 1/3) - 1 = - (4 i 1/3)

 

 

b)

dla a= -1/3   b= 4,5  c= -1  x=3 1/3    y= 0,7   z=5
abc - (abc - (-xyz - (xyz - abc))) =
abc - abc + (-xyz - (xyz - abc)) =

-xyz - (xyz - abc) = 

-xyz - xyz + abc =

-2xyz + abc =

-2(10/3)(7/10)5 + (-1/3)(9/2)(-1) =

-(10/3)(7) + (-1)(3/2)(-1) =  - 28/3 + 3/2 =    - 21 i 5/6  ( w odp powiniene być "-")

 

 

 

c) dla s=0,2   t= -5
s2t-(st2- (s2t - (st2- s2t)))=

s2t-st2 + (s2t - (st2- s2t))=

s2t - (st2- s2t) =

s2t - st2 + s2t =

s2t = 0,2* 2 * (-5) = -2

s^2*t = - 0,2

 

d) dla x=3 1/3    y= 0,7   z=5
x2yz-(xy2z-(xyz2-(x2yz-xy2z)))=

x2yz - xy2z + xyz2 - (x2yz-xy2z)=

x2yz - xy2z + xyz2 - x2yz + xy2z =

 xyz2  =

(10/3)(7/10)25 =  7/3 * 25 = 58 1/3