wyznacz ciąg geometryczny(a1,g,an) wiedzac ze a2=9 i a 5=1/3
a₅=a₂q³
1/3=9q³
q³=1/3:9=1/27
q=1/3
...............
a₂=a₁q
9=a₁×1/3
a₁=9:1/3=27
....................
an=a₁×q do potęgi (n-1)
an=27×(1/3) do potęgi (n-1)
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a₅=a₂q³
1/3=9q³
q³=1/3:9=1/27
q=1/3
...............
a₂=a₁q
9=a₁×1/3
a₁=9:1/3=27
....................
an=a₁×q do potęgi (n-1)
an=27×(1/3) do potęgi (n-1)