Matematika
Barisan Geometri
U3 = ar²
3 = a. 3²
a = 3 / 3²
a = ⅓
Bagian A
U7 = U5 × r²
U7 = 27 × 3²
U7 = 27 × 9
U7 = 243
Bagian B
Bagian C
U10 = U7 × r³
U10 = 243 × 3³
U10 = 243 × 27
U10 = 6.561
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Matematika
Barisan Geometri
U3 = ar²
3 = a. 3²
a = 3 / 3²
a = ⅓
Bagian A
U7 = U5 × r²
U7 = 27 × 3²
U7 = 27 × 9
U7 = 243
Bagian B
Bagian C
U10 = U7 × r³
U10 = 243 × 3³
U10 = 243 × 27
U10 = 6.561