24. f(x) = (1-x)/x , g o f (x) = 2x+1 => subtitusi f(x) = m
g(m) = 2x + 1
g((1-x)/x) = 2x+1
m = 1-x/x
mx = 1-x
mx+x = 1
x(m+1) = 1
x = 1/(m+1)
g(x) = g(1/(m+1))
g(1/(m+1)) = 2(1/(m+1)) + 1
= 2/(m+1)) + 1
g(x) = 2/(x+1) + 1 <= subtitusi g(x) = y
y = 2/(x+1) + 1
y - 1 = 2/(x+1)
(x+1)(y-1) = 2
xy - x + y - 1 = 2
xy - x = 3 - y
x(y-1) = -(y-3)
x = - (y-3)/(y-1)
(D)
26. f(x) = 3x-1 , g(x) = 2x²+3 . g o f (1) = ?
g o f (1) = g(f(1)) <= cari dulu nilai f(1)
f(1) = 3.1 - 1
f(1) = 2
g(f(1)) = g(2)
g(2) = 2.2²+3
= 8 + 3 = 11 (C)
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24. f(x) = (1-x)/x , g o f (x) = 2x+1 => subtitusi f(x) = m
g(m) = 2x + 1
g((1-x)/x) = 2x+1
m = 1-x/x
mx = 1-x
mx+x = 1
x(m+1) = 1
x = 1/(m+1)
g(x) = g(1/(m+1))
g(1/(m+1)) = 2(1/(m+1)) + 1
= 2/(m+1)) + 1
g(x) = 2/(x+1) + 1 <= subtitusi g(x) = y
y = 2/(x+1) + 1
y - 1 = 2/(x+1)
(x+1)(y-1) = 2
xy - x + y - 1 = 2
xy - x = 3 - y
x(y-1) = -(y-3)
x = - (y-3)/(y-1)
26. f(x) = 3x-1 , g(x) = 2x²+3 . g o f (1) = ?
g o f (1) = g(f(1)) <= cari dulu nilai f(1)
f(1) = 3.1 - 1
f(1) = 2
g(f(1)) = g(2)
g(2) = 2.2²+3
= 8 + 3 = 11 (C)