Question

a)(2/3)⁻² - (4/3)⁻¹ =

b) [(1/5)⁻³ - (1/3)⁻⁴]⁻¹ =

c) 4²*4⁻¹-7⁰ / 1+2⁻³ =

d) (1/5)⁻³ * 5⁻² + (1/5)⁻² / 10-(1/2)⁻³ =

e) 2⁻³ - (3/4)⁻² * (-1/2)² / 9⁻¹+(-1/8)⁰ =

f) 4*2⁻ ² - (3/2)⁻³ +9*3⁻¹ / 20⁻¹ * (1/5)⁻² - 16*(-4/3)⁻³ =

Answer 1

a)9/4-3/4=6/4=1i 1/2

b)(125-81)⁻¹=1/44

c)16*1/4-1/1+1/8=3/1i1/8=2 i 2/3

d)125*1/25+25/2=30/2=15

e)1/8-16/9*1/4/1/9+1=-23/80

f) 1-8/27+3/1/20*25-16*(-27/64)=5/4+27/4=32/4=8