Question

np 1/7 to jakby jedna siodma

(3,75+3,75) x (9 1/7) =

(4/5) x (15) - 1 1/3 x (1,2) =

(3 3/5) : (3/5) x 5 =

(3 3/5 : [(3/5) x 5] =

1,8 : [(0,2) x 0,3] =

1,8 : (0,2) x 0,3 =

(2,4) x 3/7 - 4,6 x 3/7 =

(5,6) x 0,75 - 2 2/5 x 0,75 =

9:1,5 - [(2,7) x (2/18) - 3/20 x 2] =

(1 1/3) x 0,75 - (1,25) x (0,8) =

Prosze o obliczenia Daje naj :D Po tym = prosze o odp .. A po = jest nastepny przyklad :D

Answer 1

[3,75+3,75]+9 1/7=7,5+9,14=16,64
[4/5]*15-1 1/3*1,2=0,8*15-1,33*1,2=12-1,596=10,404
[3 3/5]:3/5*5=3,6:0,6*5=3,6:3=1,2
[3 3/5:3/5]]*5=[3,6:0,6]*5=6*5=30
1,8:[[0,2*3]]=1,8:0,6=3
1,8:0,2*0,3=9*0,3=2,7
2,4*3/7-4,6*3/7=2,4*0,42-4,6*0,42=1,008-1,932= -0,924
5,6*0,75-2 2/5*0,75=5,6*0,75-2,4*0,75=4,2-1,8=2,4
9:1,5-[[2,7*2/18-3/20*2]]=9:1,5-[[2,7*0,11-0,15*2]=9:1,5-[0,297-0,3]=9:1,5-[-0,003]=6+0,003=6,003
[1 1/3]*0,75-1,25*0,8=1,33*0,75-1=0,9975-1= -0,0025