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sin²α+cos²α=1
(1/3)²+cos²α=1
cos²α=1-1/9
cos²α=8/9
cosα=2√2/3
sinβ=cosα i cosβ=sinα
sinβ=2√2/3
cosβ=1/3
II sposób
Z zastosowaniem wzorów redukcyjnych