Oblicz miejsca zerowe funkcji:
a) y=x/3 (ułamek)
b) y-5x+4=0
c( y=4x²-9
a) 0=x/3 /*3x=0b) y=5x-40=5x-45x=4 x= 4/5c) 0=4x²-9(2x-3)(2x+3)=02x-3=0 i 2x+3=02x=3 2x=-3x=3/2 x= - 3/2x=1,5 x=-1,5
a)
y=x/3
0=x/3/*3
0=x
x=0
b)
y-5x+4=0
y=5x-4
0=5x-4
4=5x /:5
x=4/5
c)
y=4x²-9
0=4x²-9
9=4x² /:4
x²=9/4
x₁=3/2 x₂=-3/2
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a) 0=x/3 /*3
x=0
b) y=5x-4
0=5x-4
5x=4
x= 4/5
c) 0=4x²-9
(2x-3)(2x+3)=0
2x-3=0 i 2x+3=0
2x=3 2x=-3
x=3/2 x= - 3/2
x=1,5 x=-1,5
a)
y=x/3
0=x/3/*3
0=x
x=0
b)
y-5x+4=0
y=5x-4
0=5x-4
4=5x /:5
x=4/5
c)
y=4x²-9
0=4x²-9
9=4x² /:4
x²=9/4
x₁=3/2 x₂=-3/2