Question

3) rozwiąż równania:

5x + √3x= 7

x² -7x = -10

x³ - 3x² = 0

x³ +4x³ = -4x

(x-5) = 10

4x+√3x =7

2x² - 14x = -20

x³ - 3x² =0

x³ + 4x² = -4x

(x-3) =10

Answer 1

5x + √3x = 7

x(5+√3)=7

x=2-√3

 

 

x²-7x = -10

x²-7x+10=0

Δ=49-40=9

√Δ=3

x₁=2

x₂5

 

 

x³-3x²=0

x²(x-3)=0

x²=0  lub x-3=0

x=0          x-3

 

 

x³+4x³=-4x

5x³=-4x

x³=-⅘x

x²=-⅘ - brak pierwiastków

 

 

(x-5)=10

x=15

 

 

4x+√3x=7

x(4+√3)=7

x=3-√3

 

 

2x²-14x=-20

x²-7x+10=0

Δ=49-40=9

√Δ=3

x₁=2

x₂=5

 

 

 

x³-3x²=0

x²(x-3)=0

x²=0 lub x-3=0

x=0         x=3

 

 

x³+4x²=-4x

x(x²+4x+4)=0

x=0  lub (x+2)²=0

                x+2=0

                x=-2

 

 

 

(x-3)=10

x=13