Question

1. Hasil dari (2/5)³ x (3/2)⁴ x (3/5)⁻⁵ adalah
2. Nilai dari (3¹ + 3⁰ + 3⁻¹) / (3⁻³ + 3⁻² + 3⁻¹) + (3¹ + 3⁻¹)⁻¹
3. (-2p²q³r) x (4p⁻²qr²)² adalah
4. m x 5⁻² / 15 = 5³/3 , nilai m?

Answer 1

Jawaban dan penyelesaian ada di lampiran

Answer 2

1)
(2/5)³ (3/2)⁴ (3/5)⁻⁵ =
= 2³.5⁻³. 3⁴. 2⁻⁴. 3⁻⁵. 5⁵
= 2³⁻⁴. 3⁴⁻⁵. 5⁵⁻³
= 2⁻¹ 3⁻¹. 5²
= 5²/(2¹.3¹)
= 25/6

2)
= (3¹+ 3° + 3⁻ ¹) / { (3⁻³ + 3⁻² +3⁻¹)/(3¹+3⁻¹)}       
= (3¹+ 3° + 3⁻ ¹)(3¹+3⁻¹) /  (3⁻³ + 3⁻² +3⁻¹) …(*kalikan 3³/3³)
= 3³ (3¹+ 3° + 3⁻ ¹)(3¹+3⁻¹) /  3³ (3⁻³ + 3⁻² +3⁻¹)
= (3⁴+3³+3²)(3¹+3⁻¹) / (3°+3¹+3²)
= 3²(3²+ 3¹+3°)(3¹+3⁻¹) / (3°+3¹+3²)
=  3² (3¹+3⁻¹)
= 3³+3¹
= 27 + 3
= 30

3. (-2p² q³ r)(4 p⁻² q r²)² =
=  (- 2p² . q³. r .4² .p⁻⁴. q². r⁴)
= (- 2.4². p²⁻⁴. q³⁺² . r¹⁺⁴)
= - 32.p⁻². q⁵. r⁵
= - 32 (qr)⁵/(p²)

4. (mx5⁻²)/(15) = 5³/(3)
3 m 5⁻² = 15. 5³
 m = 15/3 . 5³/5⁻²
m = 5. 5³⁺²
m = 5.5⁵
m = 5⁶