Question

1/3 log 27 x √3 log 25 + 9 3log 4

Answer 1

⅓log27 × √3log25 + 9.³log4
=-3.³log3 × ³log5 + 9.2. ³log2
= -3 × ³log5 + 18. ³log2
= 3(-1. ³log5 + 6. ³log2)
= 3(³log5^(-1) + ³log2^(6))
= 3(³log1/5 + ³log 64)
= 3(³log(1/5×64))
= 3.³log 64/5