dl,podstawy a=6x
dł. wysokosci h=3a=3·6x=18x
pole Δ P=½·a·h=½·6x·18x=54x²
x=1/3
P=54·(1/3)² =54 · 1/9 =54/9=6
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dl,podstawy a=6x
dł. wysokosci h=3a=3·6x=18x
pole Δ P=½·a·h=½·6x·18x=54x²
x=1/3
P=54·(1/3)² =54 · 1/9 =54/9=6