funkcja f(x) = (1/3) (do potęgi x)
napisz wzor funkcji g(x) = f(x+1) - 4
f(x) = (1/3)^(x)
g(x)= f(x+1) - 4,
zatem f(x+1)= (1/3)^(x+1)
a g(x)=(1/3)^(x+1) - 4 = ( (1/3)^x * 1/3 ) - 4
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f(x) = (1/3)^(x)
g(x)= f(x+1) - 4,
zatem f(x+1)= (1/3)^(x+1)
a g(x)=(1/3)^(x+1) - 4 = ( (1/3)^x * 1/3 ) - 4