a) (-2mn+1/5kl)2 m=-1/4 n = 8 k=-2 l= 10 b) ( -6ab2 c3 d4 ) 2 a=1/3 b = -0,5 c=2/3 d= -3 Pilnie potrzebne to są wyrazenia algebraiczne a te za literami i nawiasami to potegowania w a musi wyjsc 0 a w b 144
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a)
(-2mn+1/5kl)2=(-2*(-0,25)*8+0,2*(-2)*10)2=(4+(-4)2=0*2=0
b)
(-6ab² ·c³ ·d⁴)²= (-6 ·1/3 ·(-0,5)² ·(2/3)³ ·(-3)⁴)²= (-6/3 ·0,25 ·8/27 ·81)²=(-0,5 ·8/27 ·81)²= (-8/54 ·81)²= (648/54)²= 12²= 144