Question

a) (-2mn+1/5kl)2 m=-1/4 n = 8 k=-2 l= 10 b) ( -6ab2 c3 d4 ) 2 a=1/3 b = -0,5 c=2/3 d= -3 Pilnie potrzebne to są wyrazenia algebraiczne a te za literami i nawiasami to potegowania w a musi wyjsc 0 a w b 144

Answer 1

a) (-2mn+1/5kl)² = (-2·(-1/4)·8+1/5 ·(-2) ·10)²= (2/4 ·8 - 2/5 ·10)²= (16/4 - 20/5)²= (4-4)²=0²=0

 

b) (-6ab² ·c³ ·d⁴)²= (-6 ·1/3 ·(-0,5)² ·(2/3)³ ·(-3)⁴)²= (-6/3 ·0,25 ·8/27 ·81)²=(-0,5 ·8/27 ·81)²= (-8/54 ·81)²= (648/54)²= 12²= 144

 

 

 

 

Answer 2

[-2mn+1/5kl]2= [-10mn+1kl]2= -20mn+2kl= -20*[-1/4]*8+2*[-2]*10=40+[-40]=0
[-6ab^c3d4]^=[-6*1/3*[0,5]^*[2/3]3*[-3]4=[-6/3*0,25*8/27*81]^=[-0,5*8/27*81]^=[648/54]^=12^=144