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h=wysokość
h=2a
v=⅓a²h=⅓a²×2a=⅔a³
⅔a³=5⅓cm³
a³=¹⁶/₃׳/₂
a³=8cm
a=2cm
h=2a=4cm
z pitagorasa obliczam h ściany bocznej
h²=4²+1²
h²=16+1
h=√17
pole=a²+4×½ah=2²+2×2×√17=4+4√17=4(1+√17)cm²