Dane są liczby:
a=4 1/3 , b=30 ,c=jest liczba 3razy wieksza od szescianu liczby 2
znajdz liczbe ktorej 40% jest rowne a+b+c
:)
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Dane:
a = 13/3
b = 30
c = 3 x 2³ = 3 x 8 = 24
y = ?
40% z y = a + b + c
0,4y = 13/3 + 30 + 24
0,4y = 13/3 + 54
0,4y = 13/3 + 162/3
0,4y = 175/3 / * 3
1,2y = 175 /* 10
12y = 1750 / :12
y = 145 10/12
y = 145 5/6