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4+10x<x+6
x<2/9
xe(-nieskonczonosci,2/9)
b)-0,3(x+2)-3(0,2x-0,3)>0,1x
-0,3x-0,6-0,6x+0,9>0,1x
-x>-0,3
x<0,3
xe(0,3;nieskonczonosci)
c)1/4(8x-1)-2/3(6+9x)<rowne1
2x-1/4-4-6x<rowne1
-4x<rowne5 1/4
x>rowne 21/4^(-1/4)
x>rowne -1 5/16
xe(-nieskonczonosci,-1 5/16>