potęga o wykładniku całkowitym a) (-3)-3 b) (1/2)-5 c)(-2/3)-1 d)(-0,2)-3
a) (-3)^-3=(-1/3)³=-1/27
b) (1/2)^-5=2^5=32
c) (-2/3)^-1=-3/2=-1,5
d) (-0,2)^-3=(-1/5)^-3=(-5)³=-125
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a) (-3)^-3=(-1/3)³=-1/27
b) (1/2)^-5=2^5=32
c) (-2/3)^-1=-3/2=-1,5
d) (-0,2)^-3=(-1/5)^-3=(-5)³=-125
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