Rozwiąż układ równań:
x/2 + y/4 = 2x + 3y - 1/2
x(y-x) 0 - 6 = y(x-1) - x(x-2)
x/2 + y/4 = 2x + 3y - 1/2 *4
2x+ y= 8x + 12y - 2
xy- X2- 6= yx- y- x2+ 2x
2x+ y- 8x- 12y= -2
xy- x2- yx+ y+ x2+ 2x= 6
-6x- 11y= -2
y+ 2x= 6
y= 6- 2x
-6x - 11(6- 2x)= -2
-6x - 66+ 22x= -2
y=6- 2x
16x= 64 /16
x= 4
y= 6- 2*4
y= -2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x/2 + y/4 = 2x + 3y - 1/2 *4
x(y-x) 0 - 6 = y(x-1) - x(x-2)
2x+ y= 8x + 12y - 2
xy- X2- 6= yx- y- x2+ 2x
2x+ y- 8x- 12y= -2
xy- x2- yx+ y+ x2+ 2x= 6
-6x- 11y= -2
y+ 2x= 6
y= 6- 2x
-6x - 11(6- 2x)= -2
y= 6- 2x
-6x - 66+ 22x= -2
y=6- 2x
16x= 64 /16
y=6- 2x
x= 4
y= 6- 2*4
x= 4
y= -2