Question

2x(kwadrat) -3x+1=0

oblicz delte, x1,x2

Answer 1

2x^2-3x+1=0

delta= 9-8=1

x1=(3-1)/4= 1/2
x2=(3+1)/4=1

Answer 2

Delta = b^2 -4ac= (-3)^2 - 4*2*1 = 9 - 8 =1
Pierw. z delty to 1.

x1 = -b-pierw. z delty / 2 = -(-3) - 1 / 4= 2/4 = 1/2
x2 = -b- +pierw. z delty / 2 = -(-3) +1/4= 4/4=1

Answer 3

2x^{2}-3x+1 = 0
a=2 b=-3 c=1

delta = b^{2}-4ac

delta = (-3)^{2}-4*2*1

delta = 9-8

delta = 1

pierw. z delty = 1

x1 = (-b-pierw. z delty)/2a

x1 = (3-1)/4 = 1/2

x2 = (-b+pierw. z delty)/2a
x2 = (3+1)/4 = 1