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(2x-5)+(x-1) / (x-1)(2x-5) = 1
2x - 5 + x - 1 = (x-1)(2x-5)
3x - 6 = 2x² - 5x - 2x + 5
2x² - 5x - 2x - 3x + 5 + 6 = 0
2x² - 10x + 11 = 0
a = 2
b = -10
c = 11
x = [ -(-10) ± √(-10)²-4(2)(11) ] / 2(2)
x = [ 10/4 ± 2√3 / 4 ]
x = 5/2 ± √3 /2
x = (5+√3) / 2 ó x = (5-√3) / 2