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Δ=4-4*3*-1=4+12=16 √Δ=4
x1=
x1=-1 x2=
f(x)=*2x^2+2x-1
Δ=64+80=144 √Δ=12
x1= x2=
x1=1 x2=-5
f(x)=
Δ= 16+4*1/2*-4=16+16=32 √Δ= 2√4
x1= 4-2√4 x2= 4+2√4
Δ=4-24=-20 miejsce zerowe nie istnieje