rozwiąż nieróność
1. (3-x)² - (x + ⅓) ²= 2/9
2. 4 (1/2x - 3) ² - (2-x) ²= 0
3. (x-3) = 5
4. x ² - 16 = 0
5. 2x²- 72 = 0
6. x² +2 = 0
7. x²- 7 = 0
8. x² + 6 = 0
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1. (3-x)² - (x + ⅓) ²= 2/9
9x-1/4x=2/9
9i1/4x=2/9
x=37/4:2/9
x=37/4*9/2
x=333/8
x=41i 5/8
Mam nadzieje, że jest dobrze rozwiązane...;D
(3-x)² - (x + ⅓) ²= 2/9
9-6x+x²- (x²+2/3x+1/9)=2/9
9-6x+x²-x²-2/3x-1/9=2/9
-6x-2/3x=2/9-9+1/9......../*-1
6x+2/3X=-2/9+9-1/9
20/3x=80/9........../:20/3
x=80/9*3/20
x=4/3
x=1 i 1/3
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4 (1/2x - 3) ² - (2-x) ²= 0
4(1/4x²-3x+9)-(4-4x+x²)=0
x²-12X+36-4+4x+x²=0
-8x=-32.........../:-8
x=4
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(x-3) = 5
x=5+3
x=8
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4. x ² - 16 = 0
x²=16
x=4
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5. 2x²- 72 = 0
2x²=72
x²=36
x=6
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6. x² +2 = 0
x²=-2
brak rozwiązań
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7. x²- 7 = 0
x²=pierwiastek z 7
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8. x² + 6 = 0
to samo co 6
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