Dal jakiej wartości m na prostej o równaniu 2x-y+2=0 leży punkt C =(2m, 1/2m)
C=(2m;0,5m)
2x-y+2=0
y=2x+2
0,5m=2·2m+2
0,5m=4m+2
3,5m=-2
7m=-4
m=-⁴/₇
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
C=(2m;0,5m)
2x-y+2=0
y=2x+2
0,5m=2·2m+2
0,5m=4m+2
3,5m=-2
7m=-4
m=-⁴/₇