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log3/log2=a
log3= log2×a
log 2 = log3/a
=> '3log5=b
log5/log3= b
log 5= log3×b
=> '6log45 = log 45/log 6
= 2× log 3 + log 5/log2 + log 3
=2× log 3 + log3b / log3/a + log3
= 2×log3 + log3b
-----------
log3+log3a/a
= a(2log3+log3b)/ log3+log3a
= 2log 3a+ log3ab/log3+log 3a
= 2a+ab/1+a
= a(2+b)/a+1