Question

(2a-b)²+0,5(a-2b)(a+2b)
(2a-3)(2a+3)-3(a-5)²
(4x-3)(4x+3)-4(2x-1)²
5(3-5x)²-5(5x-3)(5x+3)
4(8-8(3a-1))-16a²-3(6-8a)
(√3+x)²-2(√3-x)²+2x

daje naj ;]

Answer 1

4a²-4ab+b²+0,5a²-2b²=4,5a²-4ab-b²

4a²-9-3(a²-10a+25)=4a²-9-3a²+30a-75=a²-84+30a

16x²-9-4(4x²-4x+1)=16x²-9-16x²+16x-4=-13+16x

5(9-30x+25x²)-125x²+45=45-150x+125x²-125x²+45=90-150x

32-96a+32-16a²-18+24a=46-72a-16a²

3+2√3x+x²-2(3-2√3x+x²)+2x=3+2√3x+x²-6+4√3x-2x²+2x=-3+6√3x-x²+2x


chyba OK

Answer 2

(2a-b)²+0,5(a-2b)(a+2b) = 4a²-4ab+b²+0,5(a²-4b²) = 4a²-4ab+b²+0,5a²-2b² = 4,5a²-b²-4ab

(2a-3)(2a+3)-3(a-5)² = 4a²-9-3(a²-10a+25) = 4a²-9-3a²+30a-75 = a²+30a-84

(4x-3)(4x+3)-4(2x-1)² = 16x²-9-4(4x²-4x+1) = 16x²-9-16x²+16x-4 = 16x-13

5(3-5x)²-5(5x-3)(5x+3) = 5(9-30x+25x²)-5(25x²-9) = 45-150x+125x²-125x²+45 =
-150x+90

4(8-8(3a-1))-16a²-3(6-8a) = 4(8-24a+8)-16a²-18+24a = 32-96a+32-16a²-18+24a =
-16a²-72a+46

(√3+x)²-2(√3-x)²+2x = 3+2√3x+x²-2(3-2√3x+x²)+2x = 3+2√3x+x²-6+4√3x-2x²+2x =
-x²+6√3x+2x-3 = -x²+2x(1+3√3)-3