Question

Berapakah jumlah dua belas suku pertama deret berikut.
a. 32+16+8+...
b. 1/3+1/9+1/27+...

Answer 1

A.
r=16/32
r=0,5
a= 32

S12=a(r^n-1)/r-1
32(0,5^12 - 1)/-0,5
S12= 63,98438

b. 
r= 1/9 x 3
r= 1/3
a= 1/3

S12= a(r^n-1)/r-1
1/3(1/3^12 - 1)/1/3 -1
S12= 0,499

Answer 2

A)    r = 16/32 = 1/2
       S₁₂ =