Rozwiąż nierówność:
-1/2(2x+1)^2+3(2x-1)^2 > 10x^2
^ -potęga
-1/2(4x^2+4x+1)+3(4x^2-4x+1)>10x^2
-2x^2-2x-1/2+12x^2-12x+3>10x^2
-10x^2-14x+2,5>10x^2
-14x>-2.5
14x<2,5
x<5/28
xE(5/28;+oo)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
-1/2(2x+1)^2+3(2x-1)^2 > 10x^2
-1/2(4x^2+4x+1)+3(4x^2-4x+1)>10x^2
-2x^2-2x-1/2+12x^2-12x+3>10x^2
-10x^2-14x+2,5>10x^2
-14x>-2.5
14x<2,5
x<5/28
xE(5/28;+oo)