√2+1 (√2+√3) = ? jak się to robi
i
3√2-√7 (√7+√2)
a)
(V2 + 1)/(V2 + V3) =
= (V2+1)/(V2+V3) * (V2-3)/(V2-3) = (V2+1)(V2-3)/(2-3) = (V2+1)(V2-V3)/(-1) =
= -(2-V6+V2-V3) = V6+V3-V2 -2
b)
(3V2-V7)/(V7+V2) =
= (3V2-V7)/(V7+V2) * (V7-V2)/(V7-V2) = (3V2-V7)(V7-V2)/(7-2) =
= (3V14-3*2-7+V14)/(7-2) = (4V14-13)/5
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a)
(V2 + 1)/(V2 + V3) =
= (V2+1)/(V2+V3) * (V2-3)/(V2-3) = (V2+1)(V2-3)/(2-3) = (V2+1)(V2-V3)/(-1) =
= -(2-V6+V2-V3) = V6+V3-V2 -2
b)
(3V2-V7)/(V7+V2) =
= (3V2-V7)/(V7+V2) * (V7-V2)/(V7-V2) = (3V2-V7)(V7-V2)/(7-2) =
= (3V14-3*2-7+V14)/(7-2) = (4V14-13)/5