Potrzebuję na czwartek (16.05) zadanie (układy równań):
a)
{x + 2y = 4
{2x - y = 3
b)
{2x = 5 - 3y
{4x + 6y = 10
c)
{x (x + 1) - y (y-1) = (x-y) (x+y)
{x+y/2 - x-y/2 = x
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a)
{x + 2y = 4
{2x - y = 3
x = 4 - 2y
2(4 - 2y) - y = 3
x = 4 - 2y
8 - 4y - y = 3
x = 4 - 2y
-5y = -5 /:(-5)
x = 4 - 2y
y = 1
x = 4 - 2*1
y = 1
x = 2
y = 1
b)
{2x = 5 - 3y /:2
{4x + 6y = 10
x = 2,5 - 1,5y
4(2,5 - 1,5y) + 6y = 10
x = 2,5 - 1,5y
10 - 6y + 6y = 10
x = 2,5 - 1,5y
0 = 0 Układ równań nieoznaczony.
c)
{x(x + 1) - y(y-1) = (x-y)(x+y)
{x + y/2 - x -y/2 = x
x^2 - x^2 + x - y^2 + y^2 + y = 0
-x = 0 /:(-1)
x + y = 0
x = 0
y = -x
x = 0
x = 0
y = 0