Jeżeli a=1,(4) b=1,2 do potęgi 2 c=2pod pierwiastkiem d=1 i 1/2 (ułamek)to:
A. a<b<c<d B.c<b<a<d C.d<a<c<b D. d<c<b<a
a = 1,(4), b = (1,2)^2, c = V2, d = 1 1/2 = 1,5
Odp. B. c < b < a < d
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a = 1,(4), b = (1,2)^2, c = V2, d = 1 1/2 = 1,5
Odp. B. c < b < a < d