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= ∫ (6x²-6x-36) dx
= 2x³ - 3x² - 36x + C
2. ∫ Θsin3Θ dΘ
misal:
u = Θ
du = dΘ
dv = sin3Θ dΘ
v = -(1/3)cos 3Θ
∫ Θsin 3Θ dΘ = u.v - ∫ vdu
= -(Θ/3).cos Θ + ∫ (1/3)cos 3Θ dΘ
= -(Θ/3).cos Θ +(1/9)sin 3Θ + C
= (1/9)(sin 3Θ - 3Θ.cos 3Θ) + C
3. ∫ [(3t + 4)/(2 - t)] dt
misal u = 2-t
du = -dt
∫ -[(10-3u)/u] du
= ∫ -10/u + 3 du
= -10.ln u + 3u + C
= -10.ln (2-t) + 6 - 3t + C ← rada janggal buat 6..
4. ∫ ln |y| dy - ∫ 1 dy
= (y/2).sgn(y).[ln (y) - ln(-y)]+ (y/2)ln (y) + (y/2)ln (-y)) - ∫2 dy
= (y/2).sgn(y).[ln (y) - ln(-y)]+ (y/2)ln (y) + (y/2)ln (-y)) - 2y + C
kagak paham ini signum..... T_T