Question

1.

a)(k+2)² =

b)(3x+1)² =

c) (2k+m)² =

d)(t+5w)² =

e)(x +1/2)² =

f)(a+<w pierwiastku2>)² =

2.

a) (5-x)² =

b)(b-1)² =

c) (4a-b)² =

d) (tw-7)² =

Answer 1

1.

a) (k+2)²=k²+4k+4

b) (3x+1)²= 3x²+6x+1²

c) (2k+m)²=2k²+4km+m²

d) (t+5w)²=t²+10tw+5w²

e) (x +1/2)²=x²+x+1/2²

f) (a+√2)²=a²+2√2a+√2²

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2.

a) (5-x)²=5²-10x+x²

b) (b-1)²=b²-2b+1²

c) (4a-b)²=4a²-8ab+b²

d) (tw-7)²= tw²-14tw+7²

Answer 2

a)(k+2)²  =k² +4k+4

b)(3x+1)² =9x² +6x+1

c)(2k+m)²=4k²+4km+m²

d)(t+5w)²=t²+10tw+25w²

e)(x+½)² =x²+x+¼

f)(a+√2)²=a² +2√2a+2

zad2

a)(5-x)² =25 -10x+x²

b)(b-1)² =b² -2b+1

c)(4a-b)² =16a² -8ab+b²

d)(tw-7)² =t²w²-14tw +49