Question

Rozwiąż: 3(x-2)=1/3x+10 i sprawdz.
Rozwiąż: a) x+41=(2x+13)-(x-28) b)6x-x+(2x+3)=3(2-x)
c)x/3-x/6=4+x/2 d) 2x+15=16(1+0,125x)

Answer 1

3x - 6 = 1/3 x +10
3x- 1/3x = 10+6
2 2/3x = 16 /* 3/8
x = 6
3 (6 -2) = 3 * 4 = 12
1/3 * 6 +10 = 2 +10= 12

x+41 = (2x+13) - (x-28)
x+41 = 2x+13 - x +28
x+41 = x +41
0=0
 6x - x +2x+3 = 6 - 3x
7x +3 = 6 - 3x
10 x = 3
x = 3/10

x/3-x/6 = 4 +x/2    /*6
2x - x = 24 + 3x
-2x = 24  /:-2
x= -12

2x+15 = 16 + 2x
2x - 2x= 16 -15
0x = 1  równanie nieprawdziwe