Dany jest wielomian W (x) = (x2 -16) (2x+6) (x-m).Jesli iloczyn pierwiastkow tego wielomianu jest rowny 24. to A. m= -1/2 B. m=1/2 C. m= -2 D. m= 2
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x²-16=0
x= 4 lub x=-4
2x+6=0
x=-3
x-m=0
x=m
(-4)×4×(-3)×m = 24
48m=24
m=½
odp. B