Mam do rozwiązania równanie: n + n( n - 3)/ 2 = 45 Daję naj !
2n+n(n-3)=90
2n+n²-3n=90
n²-n-90=0
Δ=(-1)²-4*1*(-90)=1+360=361
√Δ=√361=19
x₁=(1-19)/2=-9
x₂=(1+19)/2=10
ODP; n1=10 n2=-9
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2n+n(n-3)=90
2n+n²-3n=90
n²-n-90=0
Δ=(-1)²-4*1*(-90)=1+360=361
√Δ=√361=19
x₁=(1-19)/2=-9
x₂=(1+19)/2=10
ODP; n1=10 n2=-9