przedstaw liczbę w postaci a^x gdzie a jest liczbą naturalną.
a) 2^√3 * √2
b) 9^√5/2 * 27^-1
c) 27 * (3 ^ -√3)^2
a) 2^√3 * √2 = 2^√3 * 2^(1/2) = 2^(√3 + 1/2)
b) 9^√5/2 * 27^-1 = 1/2 * (3^2)^√5 * (3^3)^-1 = 1/2 * 3^2√5 * 3^-3 = 1/2 * 3^(2√5 - 3)
c) 27 * (3 ^ -√3)^2 = 27 * 3^3 = 3^3 * 3^3 = 3^6
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a) 2^√3 * √2 = 2^√3 * 2^(1/2) = 2^(√3 + 1/2)
b) 9^√5/2 * 27^-1 = 1/2 * (3^2)^√5 * (3^3)^-1 = 1/2 * 3^2√5 * 3^-3 = 1/2 * 3^(2√5 - 3)
c) 27 * (3 ^ -√3)^2 = 27 * 3^3 = 3^3 * 3^3 = 3^6