1.wysokosc trojkata jest3 razy dluzsza od podstawy i wynosi 12cm.Jakie pole ma ten trójkat? 2.zamień na hektary 200,000m kwadratowych i 57a
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1. 12:3=4cm
dane:
a=4cm
h=12cm
wzór: 1/2a x h
1/2 4 cm x 12cm
2cm x 12 cm
P=24cm2
2.200000m=20 ha
57a=0,57ha
2.
200k m2 = 20 h
100m2 = 1 a
57 a = 0,57h
1.p= 12cm x ( 12:3) :2= 12cm x 4 : 2 = 48 : 2 = 24 cm
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