1).Wykonaj mnożenie. (x + 7) (2x - 1)= (2a - 1) (a + 3)= (4a - 1) (2a - 3)=
2).Zapisz w jak najprostszej postaci. a). (a + b) (a - 2b)= b). 5 (4x - 7) - (7 - 4x)= c). 2 (3x - 2y + 3z) - 5 by - x - z)=
3).Oblicz pole i obwód koła. a). r = 3cm b). r = 4dm c). r = 5m
4).Oblicz √ 36+64 = √ 13 ² -12 ² = √ 36 - √ 81 = √ 144 -√ 100=
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1, a) (x+7)(2x-1)=2x²-x+14x-7=2x²+13x-7
b) (2a-1)(a+3)=2a²+6a-a-3=2a²+5a-3
c) (4a-1)(2a-3)=8a²-12a-2a+3=8a²-14a+3
2 a) (a+b)(a-2b)=a²-2ab+ab-2b²=a²-ab-2b²
b) 5(4x-7)-(7-4x)=20x-35-7+4x=24x-42
tyle umiem ;D