October 2018 1 17 Report

1Usuń niewymierności

\frac{14}{\sqrt{7}}=

\frac{9}{2\sqrt{3}}=

\frac{5}{\sqrt{2}+1}=

2Wyłącz czynnik przed \sqrt{}

 \sqrt{28}=

 \sqrt{125}=

\sqrt[3]{32}=

\sqrt[3]{108}=

3Włącz czynnik pod \sqrt{}

2\sqrt{3}= </p> <p>9\sqrt{5}= </p> <p>4 \sqrt[3]{2}=</p> <p> 5 \sqrt[3]{3}=


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