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x^2 + x^2 + x + x + 1 + x^2 + 2x + 2x + 4 = 245
3x^2 + 6x + 5 = 245
3x^2 + 6x = 240
x^2 + 2x = 80
x1 = 8
x2 = -10
A że mają byc to liczby naturalne: 8, 9, 10
2) x^2 + ( x + 2 )^2 + ( x + 4 )^2 = 155
x^2 + x^2 + 2x + 2x + 4 + x^2 + 4x + 4x + 16 = 155
3x^2 + 12x + 20 = 155
3x^2 + 12x = 135
x^2 + 4x = 45
x1 = 5
x2 = -9
Są to: 5, 7, 9 lub -9, -7, -5