1.Rozwiąż równania :
a) 2x² +5x -12 =0
a)
2x²+5x-12 = 0
a = 2, b = 5, c = -12
Δ = b²-4ac = 5²-4·2·(-12) = 25+96 = 121
√Δ = 11
x1 = (-b-√Δ)/2a = (-5-11)/4 = -4
x2 = (-b+√Δ)/2a = (-5+11)/4 = 1,5
Odp. x = -4 v x = 1,5
2x² + 5x - 12 = 0
Δ = b² - 4ac
Δ = 5² - 4 x 2 x (-12) = 25 - (-96) = 121
x₁ = -b-√Δ/2a
x₁ = -5 - 11/2 x 2 = -4
x₂ = -b+√Δ/2a
x₂ = -5 +11/4 = 1,5
odp. x = -4 ∨ x = 1,5
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a)
2x²+5x-12 = 0
a = 2, b = 5, c = -12
Δ = b²-4ac = 5²-4·2·(-12) = 25+96 = 121
√Δ = 11
x1 = (-b-√Δ)/2a = (-5-11)/4 = -4
x2 = (-b+√Δ)/2a = (-5+11)/4 = 1,5
Odp. x = -4 v x = 1,5
2x² + 5x - 12 = 0
Δ = b² - 4ac
Δ = 5² - 4 x 2 x (-12) = 25 - (-96) = 121
√Δ = 11
x₁ = -b-√Δ/2a
x₁ = -5 - 11/2 x 2 = -4
x₂ = -b+√Δ/2a
x₂ = -5 +11/4 = 1,5
odp. x = -4 ∨ x = 1,5
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)