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a)(√3+1)(2√3-2)=2√9-2√3+2√3-2
b)(√2+√3)(√6+√3)=√12+√6+√18+√9=2√3+√6+3√2+3
c)(x√2+1)(x-2√2)=x²√2-2x√4+x-2√2=x²√2-4x+x-2√2
d)(x+√2)(2√2+x)=2x√2+x²+4+x√2
2.
a)(x+1)(x+2)(x+3)=(x²+2x+x+2)(x+3)=x³+3x²+2x²+6x+x²+3x+2x+6
b)(x-2)(x+5)(2x-1)=(x²+5x-2x-10)(2x-1)=2x³-x²+10x²-5x-4x²+2x-20x+10
c)(x-4)(x+1)²=(x-4)(x²+2x+1)=x³+2x²+x-4x²-8x-4
d)(2x-3)²(x+2)=(4x²-12x+9)(x+2)=4x³+8x²-12x²-24x+9x+18
Oto chyba chodziło:)))