Question

1)Larutan H2SO4 pekat 98% sebanyak 1.8
mL;massa jenis 1.8 kg L^-1 dilarutkan dalam 200 mL air.Tntukan pH

Answer 1

M₁= (10 x massa jenis x %) / Mr
M₁ = (10 x 1,8 x 98) / 98
M₁ = 18 M

M₁V₁=M₂V₂18 x 1,8 = 200 M₂
M₂= 1,62 x 10⁻¹
H⁺ = a x M
H⁺ = 2 x 1,62 x 10⁻¹
H⁺ = 3,24 x 10⁻¹
PH = 1 - log 3,24